How many combinations are there with 80 numbers?
Using the combinations calculator – http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html – the total amount of possible numbers drawn in a game (80), and how many sets of 6 I can create using those 80 numbers (without repetition or order being important) – ends up to be 300,500,200.
How do you calculate the number of possible combinations?
Remember, the formula to calculate combinations is nCr = n! / r! * (n – r)!, where n represents the number of items, and r represents the number of items being chosen at a time.
How many combinations are there with 60 numbers?
Using the same argument as above there are 60 60 = 3600 two “digit” combinations and 60 60 60 = 216000 three “digit” combinations.
How do I get a list of all combinations?
combinations() to find all combinations of a list. Call itertools. combinations(iterable, r) with a list as iterable to return a combinations object containing all combinations of the list that have length r . Call list() to convert this object to a list.
How many permutations are there in 10 numbers?
If repetition is allowed, then the number of permutations of 10 digits is 10,000,000,000. If repetition is not allowed, then the number of permutations of 10 digits is 3,628,800.
How do you find all the combinations with 3 numbers?
There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6. 720 / 6 = 120.
How many combinations of 7 numbers are there?
127
The number of combinations that are possible with 7 numbers is 127.
How many combinations of 6 numbers are there in 59?
45,057,474
Answer and Explanation: The number of combinations possible with 6 numbers between 1 and 59 is 45,057,474.
How many numbers can you make with 3 numbers?
There are 3 x 2 x 1 = 6 ways to arrange the three digits. In the set of 720 possibilities, each combination of three digits is represented six times. So let’s just divide by 6. 720/6 = 120.
How do you find all the unique combinations?
Use a list comprehension for a more compact implementation.
- list1 = [“a”, “b”, “c”]
- list2 = [1, 2]
- all_combinations = [list(zip(each_permutation, list2)) for each_permutation in itertools. permutations(list1, len(list2))] Get all combinations of `list1` and `list2`
- print(all_combinations)
How do you find all possible combinations without repetition?
The number of k-element combinations of n objects, without repetition is Cn,k = (n k ) = n! k!( n − k)! . The counting problem is the same as the number of ways of putting k identical balls into n distinct boxes, such that each box receives at most one ball.